kur sheit ir kljuuda (ja ir…)

APAR     CSECT
         using *,15
         SAVE  (14,12),,*
         st    13,savearea+4 save link to the old savearea (backward)
         lr    14,13         address of the old save area
         cnop  0,4
         bal   13,codestrt
         drop  15
         using *,13
savearea dc    18F'0'
codestrt equ   *
         st    13,8(14)      set link to the new save area (forward)
*  here comes your code
*        register 1 contains address of the address list of parameters
         LM    3,4,0(1) 3=A(arr),4=L
         LTR   4,4 vai kautkas tur ir?
         BC    12,schluss
         LA    7,4 j=1
         LR    5,4 garumu pareizinam ar sizeof(int)
         M     4,=F'4' skat. iepr.
forstrt  EQU *
         LR    4,7 4reg samaitaats tagad tur buus i
         S     4,=F'4' i=j-1
         L     6,0(3,7) ieksh r6 = k
         LA    7,4(7) j++
ciklis   EQU *
         LTR   4,4   ja i ir < 0
         BC    6,eocikl  ejam aaraa no ciklis eku kljuuda!!!
         L     9,0(3,4)  r9 = arr i
         CR    6,9  k<arr i ?
         BC    12,else
         ST    9,4(3,4) arr i+1 = arr i
         S     4,=F'4'  i--
         LTR   4,4
         BC    10,ciklis
         ST    6,0(3) arr 0 = k
         B     ciklis
else     EQU *
         ST    6,4(3,4) arr i+1 = k
         LA    4,0
         S     4,=F'1'
         B     ciklis
eocikl   EQU *
         CR    7,5 j=l?
         BNE   forstrt  nav? tad turpinam ciklu
*  here ends your code
schluss  l     13,4(13)    get pointer to the old save area
         RETURN (14,12),RC=(15)
*
*  here start your data
VARSTART equ   *
VAREND   EQU   *
         END